Question

How do you find `abs( 2sqrt3 - πi )`?

Answer 1

For a complex number, `abs(a+bi)=sqrt(a^2+b^2)`, or the distance of the segment.

So, `abs(2sqrt3-pi i)=sqrt((2sqrt3)^2+(-pi)^2)=sqrt(4(3)+pi^2)=sqrt(12+pi^2)`.