How do you find #abs( 3-2i )#?

1 Answer
Jun 12, 2016

#|3-2i| = sqrt(13)#

Explanation:

The modulus of a complex number #a+bi#, denoted #|a+bi|#, is given by

#|a+bi| = sqrt(a^2+b^2)#

and represents the distance of that number from the origin on the complex plane. Note that this is analogous to the absolute value of a real number.

For our given number, #3-2i#, we have

#|3-2i| = sqrt(3^2+(-2)^2) = sqrt(9+4) = sqrt(13)#