Question

How do you find `abs( -3+4i)`?

Answer 1

`|-3+4i|=sqrt((-3)^2+4^2)=5`

Explanation:

Let `z=x+iy` be any complex number in rectangular form.

Then its modulus is given by `|z|=sqrt(x^2+y^2)`.

So in this case we get

`|-3+4i|=sqrt((-3)^2+4^2)=sqrt25=5`