Question

How do you find `abs( -3 + 7i )`?

Answer 1

`|-3+7i|=sqrt58`

Explanation:

Absolute value of a complex number `a+bi` is written as `|a+bi|` and is equal to `sqrt(a^2+b^2)`

Hence absolute value of `-3+7i` is

`|-3+7i|=sqrt((-3)^2+7^2)=sqrt(9+49)=sqrt58`