How do you find #abs( 4-8i )#?
1 Answer
Aug 18, 2016
Explanation:
Given the complex number 4 - 8 i =(4 ,-8). If we plot (4 ,-8) then the distance( r ) from the origin to the point can be calculated using
#color(blue)"Pythagoras' theorem"#
#rArrr=sqrt(x^2+y^2)# here x = 4 and y = - 8
#rArrr=|4-8i|=sqrt(4^2+(-8)^2)=sqrt80=4sqrt5#