How do you find $| 4 - 8 i |$ $abs( 4-8i )$ ?

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How do you find $| 4 - 8 i |$ $abs( 4-8i )$ ?

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Answer 1 · 2016-08-18T20:15:57

$4 \sqrt{5}$ $4sqrt5$

Explanation:

Given the complex number 4 - 8 i =(4 ,-8). If we plot (4 ,-8) then the distance( r ) from the origin to the point can be calculated using $Pythagoras' theorem$ $color(blue)"Pythagoras' theorem"$

$\Rightarrow r = \sqrt{x^{2} + y^{2}}$ $rArrr=sqrt(x^2+y^2)$

here x = 4 and y = - 8

$\Rightarrow r = | 4 - 8 i | = \sqrt{4^{2} + {(- 8)}^{2}} = \sqrt{80} = 4 \sqrt{5}$ $rArrr=|4-8i|=sqrt(4^2+(-8)^2)=sqrt80=4sqrt5$

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How do you find $| 4 - 8 i |$ $abs( 4-8i )$ ?

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How do you find |4−8i|abs( 4-8i )?

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How do you find $| 4 - 8 i |$ $abs( 4-8i )$ ?