Question

How do you find `abs( 6 - 5i )`?

Answer 1

Assuming that `abs` means the magnitude of the complex number we have that

`abs(6-5i)=sqrt(6^2+5^2)=sqrt61~~7.81`

Note that the norm (or magnitude) of a complex number `a+bi`
is

`abs(a+bi)=sqrt(a^2+b^2)`

The magnitude, (or absolute value), of a complex number is the distance from the origin `(0,0)` to that number in the complex plane.