How do you find $| - 7 - 2 i |$ $abs( -7-2i)$ ?

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How do you find $| - 7 - 2 i |$ $abs( -7-2i)$ ?

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Answer 1 · 2016-05-01T18:47:25

$\sqrt{53}$ $sqrt53$

Explanation:

Given a complex number z = a + bi , then the modulus (or magnitude) is found using Pythagoras' theorem.

$| z | = | a + b i | = \sqrt{a^{2} + b^{2}}$ $|z|=|a+bi|=sqrt(a^2+b^2)$

here a = -7 and b = -2

$\Rightarrow | - 7 - 2 i | = \sqrt{{(- 7)}^{2} + {(- 2)}^{2}} = \sqrt{53}$ $rArr|-7-2i|=sqrt((-7)^2+(-2)^2)=sqrt53$

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How do you find $| - 7 - 2 i |$ $abs( -7-2i)$ ?

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How do you find |−7−2i|abs( -7-2i)?

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How do you find $| - 7 - 2 i |$ $abs( -7-2i)$ ?