How do you find #abs( 7+9i )#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer sente May 6, 2016 #|7+9i| = sqrt(130)# Explanation: Given a complex number #a+bi#, the modulus of that number, denoted #|a+bi|#, is the distance from that number to the origin on the complex plane. Then, we have #|a+bi| = sqrt(a^2+b^2)#. In this case, that gives us #|7+9i| = sqrt(7^2+9^2) = sqrt(130)# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1369 views around the world You can reuse this answer Creative Commons License