How do you find #abs(i^2)#?

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Answer 1 · 2016-04-16T19:32:11

#abs(i^2) = 1#

#i# is the square root of #-1#, or

#i = sqrt(-1)#.

Therefore,

#i^2 = -1#,

simply by the definition of a square root.

Ultimate value (#abs#) can be thought of as the distance of a certain number from #0#, always as a positive number, so

#abs(-1) = 1#

and, by extension,

#abs(i^2) = 1#