How do you find #abs(i-5 )#?
1 Answer
Jul 28, 2017
Explanation:
#"the magnitude of the complex number "z=x+yi#
#|z|=|x+yi|=sqrt(x^2+y^2)#
#"here "x=-5" and " y=1#
#rArr|i-5|=sqrt((-5)^2+1^2)=sqrt26#
