How do you find #abs( x+iy )#?
1 Answer
Mar 21, 2016
Explanation:
Using the distance formula which comes from Pythagoras theorem, we have:
#abs(x+iy) = sqrt(x^2+y^2)#
Notice that
So another way of expressing this is:
#abs(x+iy) = sqrt((x+iy)(x-iy)) = sqrt((x+iy)bar((x+iy)))#
So without explicitly splitting a Complex number
#abs(z) = sqrt(z bar(z))#