How do you find absolute value of 4+2i, 8i, and -3 + 7i?
1 Answer
Apr 15, 2018
Explanation:
#"given a complex number "x+yi#
#"then the absolute value is"#
#•color(white)(x)|x+yi|=sqrt(x^2+y^2)#
#4+2i" has "x=4" and "y=2#
#rArr|4+2i|=sqrt(4^2+2^2)=sqrt20=2sqrt5#
#8i" has "x=0" and "y=8#
#rArr|8i|=sqrt(0^2+8^2)=8#
#-3+7i" has "x=-3" and "y=7#
#rArr|-3+7i|=sqrt((-3)^2+7^2)=sqrt58#