How do you find all critical point and determine the min, max and inflection given #f(x)=2x^3-x^2+1#?
1 Answer
Jan 11, 2017
Explanation:
We can find the critical points by equating the first derivative to zero:
so the critical points are:
To determine if they are local extrema and to find inflection points we calculate the second derivative:
So we have a single inflection point at
Based on the sign of the second derivative we can also conclude that
graph{2x^3-x^2+1 [-0.3227, 0.9273, 0.7125, 1.3375]}