How do you find all points of inflection given $y = - \frac{2 x}{x + 3}$ $y=-(2x)/(x+3)$ ?

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How do you find all points of inflection given $y = - \frac{2 x}{x + 3}$ $y=-(2x)/(x+3)$ ?

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Answer 1 · 2017-07-04T21:35:08

There aren't any?!

Explanation:

I may have gone wrong with this one but when I differentiated this and put $\frac{d y}{d x} = 0$ $dy/dx = 0$ , I got a quadratic which didn't factorise. I checked online with a graph plotter and the gradient of this graph has asymptotes so am I right in thinking there are no points of inflection?

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How do you find all points of inflection given $y = - \frac{2 x}{x + 3}$ $y=-(2x)/(x+3)$ ?

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How do you find all points of inflection given y=-(2x)/(x+3)y=−2xx+3y=-(2x)/(x+3)?

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How do you find all points of inflection given $y = - \frac{2 x}{x + 3}$ $y=-(2x)/(x+3)$ ?