How do you find all the asymptotes for function f(x) = (11(x-5)^5(x+6)^5)/ (x^10+11x^5+30)f(x)=11(x5)5(x+6)5x10+11x5+30?

1 Answer
Feb 26, 2016

x=-root(5)6x=56 and x=-root(5)5x=55 are two vertical asymptotes. Horizontal asymptote is y=11y=11.

Explanation:

To find asymptotes of f(x)=(11(x−5)^5*(x+6)^5)/(x^10+11x^5+30)f(x)=11(x5)5(x+6)5x10+11x5+30, we should factorize denominator (x^10+11x^5+30)(x10+11x5+30)

The factors of (x^10+11x^5+30)(x10+11x5+30) are (x^5+5)(x5+5) and (x^5+6)(x5+6)

As (x+a)(x+a) is a factor of (x^5+a^5)(x5+a5) (as -aa is zero of latter)

two factors of (x^10+11x^5+30)(x10+11x5+30) are x=-root(5)6x=56 and x=-root(5)5x=55

and hence x=-root(5)6x=56 and x=-root(5)5x=55 are two vertical asymptotes.

It is also apparent that the highest degree of numerator is 11x^1011x10 and that of denominator is x^10x10. As their ratio is 1111

Horizontal asymptote is y=11y=11.