How do you find all the asymptotes for #(x^2 - 9)/(3x - 6)#?
1 Answer
Examine where the denominator is zero to find the vertical asymptote. Long divide to get a quotient linear polynomial that represents the oblique asymptote.
Explanation:
Let
The denominator is zero when
Long divide to get a quotient and remainder:
Then as
So the oblique asymptote is
graph{(y-(x^2-9)/(3x-6))(y-(x/3+2/3))=0 [-10, 10, -5, 5]}