How do you find all the real and complex roots of #f(x)=x^3-5x^2+11x-15#? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Cem Sentin Mar 19, 2018 #x_1=3#, #x_2=1-2i# and #x_3=1+2i# Explanation: #x^3-5x^2+11x-15=0# #x^3-3x^2-2x^2+6x+5x-15=0# #x^2*(x-3)-2x*(x-3)+5*(x-3)=0# #(x-3)*(x^2-2x+5)=0# From first multiplier, #x_1=3#. From second one #x_2=1-2i# and #x_3=1+2i# Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 1926 views around the world You can reuse this answer Creative Commons License