How do you find an equation for the tangent line to #x^4=y^2+x^2# at #(2, sqrt12)#?
2 Answers
Explanation:
at
The equation of tangent,
Explanation:
Differentiating,
The equation to the tangent at P is
y-sqrt13=7/sqrt3(x-2), giving
graph{(x^2-sqrt(x^2+y^2))(7x-sqrt3 y-8.2)=0 [-7, 7, -35, 35]}