How do you find arc length of an arc that subtends a central angle of 60 degrees in a circle with radius 25m?

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How do you find arc length of an arc that subtends a central angle of 60 degrees in a circle with radius 25m?

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Answer 1 · 2018-04-20T12:54:03

$length \approx 26.18 m to 2 dec. places$ $"length "~~26.18" m to 2 dec. places"$

Explanation:

$the length of an arc given it subtends a known angle at$ $"the length of an arc given it subtends a known angle at"$
$the centre is$ $"the centre is"$

$arc length (l) =circumference ×fraction of circle$ $"arc length (l) "="circumference "xx"fraction of circle"$

$\Rightarrow l = 2 π r \times \frac{60}{360}$ $rArrl=2pirxx60/360$

$l = 2 π \times 25 \times \frac{1}{6} = \frac{25 π}{3} \approx 26.18 m$ $color(white)(l)=2pixx25xx1/6=(25pi)/3~~26.18" m"$

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How do you find arc length of an arc that subtends a central angle of 60 degrees in a circle with radius 25m?

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