How do you find cos^-1(-sqrt2/2)? Trigonometry Inverse Trigonometric Functions Basic Inverse Trigonometric Functions 1 Answer Anjali G Nov 30, 2016 cos^-1(-sqrt2/2) = (3pi)/4 Explanation: Think about the unit circle -- "Where is cosine equal to -sqrt2/2?". This comes up with values: (3pi)/4 and (5pi)/4, but because the domain of cos^-1 is restricted to [0,pi], we only list (3pi)/4 in the answer. Answer link Related questions What are the Basic Inverse Trigonometric Functions? How do you use inverse trig functions to find angles? How do you use inverse trigonometric functions to find the solutions of the equation that are in... How do you use inverse trig functions to solve equations? How do you evalute sin^-1 (-sqrt(3)/2)? How do you evalute tan^-1 (-sqrt(3))? How do you find the inverse of f(x) = \frac{1}{x-5} algebraically? How do you find the inverse of f(x) = 5 sin^{-1}( frac{2}{x-3} )? What is tan(arctan 10)? How do you find the arcsin(sin((7pi)/6))? See all questions in Basic Inverse Trigonometric Functions Impact of this question 2130 views around the world You can reuse this answer Creative Commons License