How do you find #(d^2y)/(dx^2)# for #2x-5y^2=3#?
2 Answers
Explanation:
Let's substitude from the equation
So we get :
Explanation:
Differentiate both sides of the equation with respect to
and differentiating again:
substitute now
We can also have an implicit equation for
and substituting
Function:
graph{y^2 = (2x-3)/5 [-10, 10, -5, 5]}
Derivative:
graph{y^2 = 1/5 1/(2x-3)^3 [-10, 10, -5, 5]}