How do you find #dy/dx# by implicit differentiation of #x^2-y^3=0# and evaluate at point (1,1)?
1 Answer
Feb 22, 2017
# [dy/dx ]_{ (0,0) } =2/3#
Explanation:
When we differentiate
However, we cannot differentiate a non implicit function of
When this is done in situ it is known as implicit differentiation.
We have:
# x^2-y^3=0 #
Differentiate wrt
# 2x-3y^2dy/dx=0 \ \ \ \ # .... [1]
Although (in this case) we could find an implicit expression for
At
# 2-3dy/dx=0 => dy/dx=2/3#