How do you find $f (0)$ $f(0)$ given $f (n) = n^{2} - 4$ $f(n)=n^2-4$ ?

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Answer 1 · 2018-03-29T01:49:02

$- 4$ $-4$

Given: $f (n) = n^{2} - 4$ $f(n)=n^2-4$

When $f (0)$ $f(0)$ , we simply plug in $n = 0$ $n=0$ into the function, and we get,

$f (0) = 0^{2} - 4$ $f(0)=0^2-4$

$= 0 - 4$ $=0-4$

$= - 4$ $=-4$

Answer 2 · 2018-03-29T01:51:36

$- 4$ $-4$

Substitute $0$ $0$ for $n$ $n$ in the expression $n^{2} - 4$ $n^2-4$

$f (0) = {(0)}^{2} - 4 = 0 - 4 = - 4$ $f(0)=(0)^2-4=0-4=-4$

How do you find f(0)f(0) given f(n)=n2−4f(n)=n^2-4?