How do you find $f^-1(x)$ given $f(x)=-x-2$ ?

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Answer 1 · 2016-11-20T08:04:32

THe answer is $f^(-1)(x)=-x-2$

Let $y=-x-2$

Then, $x=-y-2$

so, $f^(-1)(x)=-x-2$

Verification,

$f(f^(-1)(x))=f(-x-2)=-(-x-2)-2$

$=x+2-2=x$

Therefore, this confirm that $f^(-1)(x)=-x-2$

How do you find f^-1(x)f^-1(x) given f(x)=-x-2f(x)=-x-2?