How do you find f(-5) given $f (x) = \frac{1}{2} | t + 3 |$ $f(x) = 1/2abs [t + 3]$ ?

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Answer 1 · 2017-06-09T17:27:00

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This make some sense if t = x and $f (x) = \frac{1}{2} | x + 3 |$ $f(x) = 1/2 | x + 3 |$

$f (- 5) = \frac{1}{2} \cdot | - 5 + 3 | = \frac{1}{2} \cdot 2$ $f(-5) = 1/2 * |-5 + 3| = 1/2 * 2$

How do you find f(-5) given f(x)=12|t+3|f(x) = 1/2abs [t + 3]?