How do you find $f(-8)$ given $f(x)=x^2-3x$ ?

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Answer 1 · 2016-08-25T09:41:23

$f(-8)=88$

To evaluate f( -8), substitute x = - 8 into f(x)

$f(color(red)(-8))=(color(red)(-8))^2-3(color(red)(-8))$

$rArrf(-8)=64+24=88$

How do you find f(-8)f(-8) given f(x)=x^2-3xf(x)=x^2-3x?