How do you find $f (g (h (2)))$ $f(g(h(2)))$ given $f (x) = 2 x - 1$ $f(x)=2x-1$ and $g (x) = 3 x$ $g(x)=3x$ and $h (x) = x^{2} + 1$ $h(x)=x^2+1$ ?

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Answer 1 · 2016-08-30T08:51:45

29

Start at the bit you can do...h(2)
h(x)= $x^{2} + 1$ $x^2+1$
h(2)= $2^{2} + 1$ $2^2+1$ =5

Next g(x)=3x
Now we are looking at g(h(2)) but we know h(2) =5
g(5) =3*5=15
So g(h(2))=15

Next f(x) =2x-1

So similarly we are looking for f(15) =2*15=29

How do you find f(g(h(2)))f(g(h(2))) given f(x)=2x−1f(x)=2x-1 and g(x)=3xg(x)=3x and h(x)=x2+1h(x)=x^2+1?