How do you find $(f - g) (x)$ $(f-g)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

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Answer 1 · 2017-04-11T17:16:38

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$(f - g) (x) = f (x) - g (x) = (x^{2} - 1) - (2 x - 3)$ $(f - g)(x) = f(x) - g(x) = (x^2 - 1) - (2x - 3)$

$(f - g) (x) = x^{2} - 1 - 2 x + 3$ $(f - g)(x) = x^2 - 1 - 2x + 3$

$(f - g) (x) = x^{2} - 2 x + 3 - 1$ $(f - g)(x) = x^2 - 2x + 3 - 1$

$(f - g) (x) = x^{2} - 2 x + 2$ $(f - g)(x) = x^2 - 2x + 2$

The $h (x)$ $h(x)$ is not used and is extraneous and unnecessary information for this problem.

How do you find (f−g)(x)(f-g)(x) given f(x)=x2−1andf(x)=x^2-1 and g(x)=2x-3and and h(x)=1-4x#?