How do you find $(f + g) (x)$ $(f+g)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

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Answer 1 · 2018-03-20T12:57:07

See a solution process below:

We can rewrite $(f + g) (x)$ $(f + g)(x)$ as:

$(f + g) (x) = f (x) + g (x)$ $(f + g)(x) = f(x) + g(x)$

Substituting gives:

$(f + g) (x) = (x^{2} - 1) + (2 x - 3)$ $(f + g)(x) = (x^2 - 1) + (2x - 3)$

$(f + g) (x) = x^{2} - 1 + 2 x - 3$ $(f + g)(x) = x^2 - 1 + 2x - 3$

$(f + g) (x) = x^{2} + 2 x - 1 - 3$ $(f + g)(x) = x^2 + 2x - 1 - 3$

$(f + g) (x) = x^{2} + 2 x + (- 1 - 3)$ $(f + g)(x) = x^2 + 2x + (-1 - 3)$

$(f + g) (x) = x^{2} + 2 x + (- 4)$ $(f + g)(x) = x^2 + 2x + (-4)$

$(f + g) (x) = x^{2} + 2 x - 4$ $(f + g)(x) = x^2 + 2x - 4$

How do you find (f+g)(x)(f+g)(x) given f(x)=x2−1andf(x)=x^2-1 and g(x)=2x-3and and h(x)=1-4x#?