How do you find $(f \cdot g) (x)$ $(f*g)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

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How do you find $(f \cdot g) (x)$ $(f*g)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

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Answer 1 · 2017-06-03T17:52:38

See a solution process below:

Explanation:

$(f \cdot g) (x) = (x^{2} - 1) (2 x - 3)$ $(f * g)(x) = (x^2 - 1)(2x - 3)$

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$(f \cdot g) (x) = (x^{2} - 1) (2 x - 3)$ $(f * g)(x) = (color(red)(x^2) - color(red)(1))(color(blue)(2x) - color(blue)(3))$ becomes:

$(f \cdot g) (x) = (x^{2} \times 2 x) - (x^{2} \times 3) - (1 \times 2 x) + (1 \times 3)$ $(f * g)(x) = (color(red)(x^2) xx color(blue)(2x)) - (color(red)(x^2) xx color(blue)(3)) - (color(red)(1) xx color(blue)(2x)) + (color(red)(1) xx color(blue)(3))$

$(f \cdot g) (x) = 2 x^{3} - 3 x^{2} - 2 x + 3$ $(f * g)(x) = 2x^3 - 3x^2 - 2x + 3$

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How do you find $(f \cdot g) (x)$ $(f*g)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

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How do you find (f⋅g)(x)(f*g)(x) given f(x)=x2−1andf(x)=x^2-1 and g(x)=2x-3and and h(x)=1-4x#?

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How do you find $(f \cdot g) (x)$ $(f*g)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?