How do you find $(f - g) (x)$ $(f-g)(x)$ when $f (x) = 6 x^{2} + 4 x - 7$ $f(x)=6x^2+4x-7$ and $g (x) = 2 x - 7 x^{2} + 11$ $g(x)=2x-7x^2+11$ ?

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How do you find $(f - g) (x)$ $(f-g)(x)$ when $f (x) = 6 x^{2} + 4 x - 7$ $f(x)=6x^2+4x-7$ and $g (x) = 2 x - 7 x^{2} + 11$ $g(x)=2x-7x^2+11$ ?

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Answer 1 · 2016-12-02T21:23:26

Simply subtract the two functions.

$(f - g) (x) = 6 x^{2} + 4 x - 7 - (2 x - 7 x^{2} + 11)$ $(f- g)(x) = 6x^2 + 4x - 7 - (2x - 7x^2 + 11)$

$= 6 x^{2} + 4 x - 7 - 2 x + 7 x^{2} - 11$ $=6x^2 + 4x - 7 - 2x + 7x^2 - 11$

$= 13 x^{2} + 2 x - 18$ $=13x^2 + 2x - 18$

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How do you find $(f - g) (x)$ $(f-g)(x)$ when $f (x) = 6 x^{2} + 4 x - 7$ $f(x)=6x^2+4x-7$ and $g (x) = 2 x - 7 x^{2} + 11$ $g(x)=2x-7x^2+11$ ?

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How do you find (f−g)(x)(f-g)(x) when f(x)=6x2+4x−7f(x)=6x^2+4x-7 and g(x)=2x−7x2+11g(x)=2x-7x^2+11?

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How do you find $(f - g) (x)$ $(f-g)(x)$ when $f (x) = 6 x^{2} + 4 x - 7$ $f(x)=6x^2+4x-7$ and $g (x) = 2 x - 7 x^{2} + 11$ $g(x)=2x-7x^2+11$ ?