How do you find $(f + h) (0)$ $(f+h)(0)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

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Answer 1 · 2017-06-01T21:44:08

See below.

$(f + h) (0) = f (0) + h (0)$ $(f+h)(0)=f(0)+h(0)$ .

Given that $f (x) = x^{2} - 1$ $f(x)=x^2-1$ ,

$f (0) = 0^{2} - 1 = - 1$ $f(0)=0^2-1=-1$

$h (0) = 1 - 4 (0) = 1$ $h(0)=1-4(0)=1$

Thus,

$(f + h) (0) = f (0) + h (0) = - 1 + 1 = 0$ $(f+h)(0)=f(0)+h(0)=-1+1=0$ .

How do you find (f+h)(0)(f+h)(0) given f(x)=x2−1andf(x)=x^2-1 and g(x)=2x-3and and h(x)=1-4x#?