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How do you find $f (n^{2})$ $f(n^2)$ given $f (n) = n^{2} - 2 n$ $f(n)=n^2-2n$ ?

1 Answer

Apr 3, 2017

$f (n^{2}) = n^{4} - 2 n^{2}$ $f(n^2) =n^4 - 2 n^2$

Explanation:

$f(n) = n^2 -2 n :. f(n^2) = (n^2)^2 -2 (n^2) =n^4 - 2 n^2$ [Ans]

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