How do you find four consecutive multiples of 5 whose sum is 90?

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How do you find four consecutive multiples of 5 whose sum is 90?

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Answer 1 · 2018-05-02T14:14:42

$15, 20, 25, 30$ $15,20,25,30$

Explanation:

We know that the multiples' will add up to 90, so their average must be $\frac{90}{4}$ $90/4$ , or $22.5$ $22.5$ . Since there are an even number of multiples (4), none of them will touch the average, but they will be centered around it. Therefore, the multiples must be $15, 20, 25, 30$ $15,20,25,30$
Check:
$15 + 20 + 25 + 30 = 90$ $15+20+25+30=90$

Answer 2 · 2018-05-02T14:38:48

$15$ $15$ , $20$ $20$ , $25$ $25$ and $30$ $30$

Explanation:

Let the smallest number of the bunch be $x$ $x$ ,

$x + (x + 5) + (x + 5 + 5) + (x + 5 + 5 + 5) = 90$ $x+(x+5)+(x+5+5)+(x+5+5+5)=90$

Simplify,

$4 x + 30 = 90$ $4x+30=90$

Subtract $30$ $30$ from both sides,

$4 x = 60$ $4x=60$

Divide,

$x = 15$ $x=15$

Since the smallest number is $15$ $15$ , the rest are as follows: $20$ $20$ , $25$ $25$ and $30$ $30$ .

Answer 3 · 2018-05-02T14:52:36

The multiples are $15, 20, 25, 30$ $" "15," "20," "25," "30$

Explanation:

Any multiple of $5$ $5$ can be written as $5 x$ $5x$

The next multiple will be when $x$ $x$ increases by $1$ $1$

The sum of four consecutive multiples of $5$ $5$ is $90$ $90$

$5 x + 5 (x + 1) + 5 (x + 2) + 5 (x + 3) = 90$ $5x +5(x+1)+5(x+2)+5(x+3)=90$

$5 x + 5 x + 5 + 5 x + 10 + 5 x + 15 = 90$ $5x +5x+5+5x+10+5x+15 = 90$

$20 x + 30 = 90$ $20x +30 =90$

$20 x = 60$ $20x = 60$

$x = 3$ $x =3$

So the first multiple of $5$ $5$ is $5 \times 3 = 15$ $5xx3=15$

The multiples are $15, 20, 25, 30$ $" "15," "20," "25," "30$

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How do you find four consecutive multiples of 5 whose sum is 90?

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