How do you find $g (1)$ $g(1)$ given $g (a) = 3^{3 a - 2}$ $g(a)=3^(3a-2)$ ?

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Answer 1 · 2017-04-17T22:09:19

See the entire solution process below:

To find $g (1)$ $g(1)$ substitute $1$ $color(red)(1)$ for each occurrence of $a$ $a$ in the function $g (a)$ $g(a)$ :

$g (a) = 3^{3 a - 2}$ $g(color(red)(a)) = 3^(3color(red)(a) - 2)$ becomes:

$g (1) = 3^{(3 \cdot 1) - 2}$ $g(color(red)(1)) = 3^((3 * color(red)(1)) - 2)$

$g (1) = 3^{3 - 2}$ $g(color(red)(1)) = 3^(3 - 2)$

$g (1) = 3^{1}$ $g(color(red)(1)) = 3^1$

$g (1) = 3$ $g(color(red)(1)) = 3$

How do you find g(1)g(1) given g(a)=33a−2g(a)=3^(3a-2)?