How do you find $g (- 1)$ $g(-1)$ given $g (x) = - 5 x + 2$ $g(x)=-5x+2$ ?

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How do you find $g (- 1)$ $g(-1)$ given $g (x) = - 5 x + 2$ $g(x)=-5x+2$ ?

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Answer 1 · 2018-03-12T01:22:42

$g (- 1) = 7$ $g(-1)=7$

Explanation:

Simply substitute the value of $- 1$ $-1$ given. In other words, $g (- 1)$ $g(-1)$ is the function of $g (x)$ $g(x)$ , however in this case, $x$ $x$ is $- 1$ $-1$

$g (- 1) = - 5 (- 1) + 2$ $g(-1)=-5(-1)+2$

Distribute $5$ $5$ through the parenthesis

$g (- 1) = 5 + 2$ $g(-1)=5+2$

Simplify

$g (- 1) = 7$ $g(-1)=7$

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How do you find $g (- 1)$ $g(-1)$ given $g (x) = - 5 x + 2$ $g(x)=-5x+2$ ?

1 Answer

Explanation:

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How do you find g(-1)g(−1)g(-1) given g(x)=-5x+2g(x)=−5x+2g(x)=-5x+2?

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How do you find $g (- 1)$ $g(-1)$ given $g (x) = - 5 x + 2$ $g(x)=-5x+2$ ?