How do you find $g (3 a)$ $g(3a)$ given $f (x) = 2 x - 1$ $f(x)=2x-1$ and $g (x) = 3 x$ $g(x)=3x$ and $h (x) = x^{2} + 1$ $h(x)=x^2+1$ ?

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Answer 1 · 2017-03-11T19:26:58

$g (3 a) = 9 a$ $g(3a)=9a$

To evaluate g( 3a) substitute x = 3a into g( x)

$\Rightarrow g (3 a) = 3 \times 3 a = 9 a$ $rArrg(color(red)(3a))=3xxcolor(red)(3a)=9a$

How do you find g(3a)g(3a) given f(x)=2x−1f(x)=2x-1 and g(x)=3xg(x)=3x and h(x)=x2+1h(x)=x^2+1?