How do you find $g (8)$ $g(8)$ given $g (n) = n^{2} + 3$ $g(n)=n^2+3$ ?

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How do you find $g (8)$ $g(8)$ given $g (n) = n^{2} + 3$ $g(n)=n^2+3$ ?

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Answer 1 · 2018-03-13T17:59:03

$g (8) = 8^{2} + 3 = 67$ $g(8)=8^2+3=67$

Explanation:

Since $g (n) = n^{2} + 3$ $g(n)=n^2+3$ and we already have $n = 8$ $n=8$ (from $g (8)$ $g(8)$ ) , all we need to do it to replace $n$ $n$ with $8$ $8$ and apply this to the equation (seen above).

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How do you find $g (8)$ $g(8)$ given $g (n) = n^{2} + 3$ $g(n)=n^2+3$ ?

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Explanation:

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How do you find $g (8)$ $g(8)$ given $g (n) = n^{2} + 3$ $g(n)=n^2+3$ ?