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How do you find $(g - f) (a)$ $(g-f)(a)$ given $g (a) = - 3 a - 3$ $g(a)=-3a-3$ and $f (a) = a^{2} + 5$ $f(a)=a^2+5$ ?

1 Answer

Jan 30, 2017

$(g - f) (a) = - a^{2} - 3 a - 8$ $(g-f)(a)=-a^2-3a-8$

Explanation:

$(g - f) (a) = g (a) - f (a)$ $(g-f)(a)=g(a)-f(a)$

$\Rightarrow - 3 a - 3 - (a^{2} + 5)$ $rArr-3a-3-(a^2+5)$

$= - 3 a - 3 - a^{2} - 5$ $=-3a-3-a^2-5$

$= - a^{2} - 3 a - 8$ $=-a^2-3a-8$

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