How do you find $(g - f) (x)$ $(g-f)(x)$ given $g (x) = - x^{2} - 1 - 2 x$ $g(x)=-x^2-1-2x$ and $f (x) = x + 5$ $f(x)=x+5$ ?

Question

25360 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-18T09:14:05

We know that $(g - f) (x) = g (x) - f (x)$ $(g-f)(x)=g(x)-f(x)$ .

$(g - f) (x) = g (x) - f (x) = - x^{2} - 1 - 2 x - x - 5 =$ $(g-f)(x)=g(x)-f(x)=-x^2-1-2x-x-5=$

$- x^{2} - 3 x - 6$ $-x^2-3x-6$

so $(g - f) (x) = - x^{2} - 3 x - 6$ $(g-f)(x)=-x^2-3x-6$

How do you find (g−f)(x)(g-f)(x) given g(x)=−x2−1−2xg(x)=-x^2-1-2x and f(x)=x+5f(x)=x+5?