Question

How do you find `g(h(24))` given `f(x)=2x-1` and `g(x)=3x` and `h(x)=x^2+1`?

Answer 1

`g(h(24))=1731`

Explanation:

Evaluate g(h(24)) by first evaluating h(24)

`rArrh(color(red)(24))=(color(red)(24))^2+1`

`color(white)(rAerrh(24))=576+1`

`color(white)(rArrh(24)xx)=577`

Now substitute this value into g(x)

`rArrg(h(24))=g(577)`

`=3xx577`

`=1731`