How do you find $(\frac{g}{h}) (x)$ $(g/h)(x)$ given $f (x) = x^{2} - 1 and$ $f(x)=x^2-1 and$ g(x)=2x-3 $and$ $and$ h(x)=1-4x#?

Question

2023 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-28T20:57:19

$(g/h)(x)=(x^2-1)/(1-4x), "where," x in RR-{1/4}$ , or,

$x in (-oo,1/4)uu(1/4,oo)$

By Defn. $(g/h)(x)=g(x)/(h(x)), "where," x in RR-{x in RR | h(x)=0}$ .

Hence, $(g/h)(x)=(x^2-1)/(1-4x), "where," x in RR-{1/4}$ , or,

$x in (-oo,1/4)uu(1/4,oo)$

How do you find (g/h)(x)(gh)(x)(g/h)(x) given f(x)=x^2-1 and f(x)=x2−1andf(x)=x^2-1 and g(x)=2x-3 and and and h(x)=1-4x#?