Question

How do you find `g(t/4)` given `g(t)=t+3`?

Answer 1

`g(t/4)=(t+12)/4`

Explanation:

To evaluate `g(t/4)`

`color(blue)"substitute t=t/4 into g(t)"`

`rArrg(color(red)(t/4))=color(red)(t/4)+3`

We can express `t/4+3" as a single fraction"`

`rArrt/4+(3/1xx 4/4)=t/4+12/4`

we now have a common denominator and can add the numerators.

`rArrg(t/4)=(t+12)/4`