How do you find $(goh)(-1)$ given $g(t)=t^2+3$ and $h(t)=4t-3$ ?

Question

7487 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-06T00:06:35

fifty-two

$g(h(-1)) = g(x)$

$x = h(-1) = 4(-1)-3 = -4-3=-7$

$g(x) = g(-7) = 7^2 + 3 = 49 + 3 = 52$

How do you find (goh)(-1)(goh)(-1) given g(t)=t^2+3g(t)=t^2+3 and h(t)=4t-3h(t)=4t-3?