How do you find $(g o h) (n)$ $(goh)(n)$ given $g (n) = 2 n + 3$ $g(n)=2n+3$ and $h (n) = n - 1$ $h(n)=n-1$ ?

Question

11472 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-31T10:02:25

The answer is $= 2 n + 1$ $=2n+1$

This is a composition of functions

$g (n) = 2 n + 3$ $g(n)=2n+3$

$h (n) = n - 1$ $h(n)=n-1$

$(g o h) (n) = g (h (n))$ $(goh)(n)=g(h(n))$

$= g (n - 1)$ $=g(n-1)$

$= 2 (n - 1) + 3$ $=2(n-1)+3$

$= 2 n - 2 + 3$ $=2n-2+3$

$= 2 n + 1$ $=2n+1$

How do you find (goh)(n)(goh)(n) given g(n)=2n+3g(n)=2n+3 and h(n)=n−1h(n)=n-1?