How do you find $h (- 1)$ $h(-1)$ given $h (n) = \frac{4}{3} n + \frac{8}{5}$ $h(n)=4/3n+8/5$ ?

Question

6528 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-20T00:59:10

$h (- 1) = \frac{4}{15}$ $h(-1)= 4/15$

Steps:
Lets first begin by finding the LCD of the two fractions so we can add them.

The LCD is $15$ $15$ so we must manipulate each fraction individually so that its denominator is $15$ $15$

Lets start with $\frac{4}{3} n$ $4/3 n$ :
To make the denominator $15$ $15$ we must multiply both the numerator and denominator by $5$ $5$ , thus:

$\frac{5}{5} \cdot \frac{4}{3} n = \frac{20}{15} n$ $5/5*4/3 n = 20/15 n$

Similarly, we must multiply both the numerator and denominator by $3$ $3$ for $\frac{8}{5}$ $8/5$

$\frac{3}{3} \cdot \frac{8}{5} = \frac{24}{15}$ $3/3*8/5=24/15$

So now we have
$h (n) = \frac{20}{15} n + \frac{24}{15}$ $h(n)= 20/15 n+24/15$

So...
$h (- 1) = \frac{20}{15} (- 1) + \frac{24}{15}$ $h(-1)= 20/15 (-1)+24/15$

$h (- 1) = - \frac{20}{15} + \frac{24}{15}$ $h(-1)= -20/15+24/15$
$h (- 1) = \frac{4}{15}$ $h(-1)= 4/15$

Answer 2 · 2017-03-20T01:01:04

$h (- 1) = \frac{4}{15}$ $h(-1)=4/15$

Since it's $h (- 1)$ $h(-1)$ plug in -1 for n.

h(-1)= $\frac{4}{3} (- 1) + \frac{8}{5}$ $4/3(-1)+8/5$

= $- \frac{4}{3} + \frac{8}{5}$ $-4/3+8/5$

= $- \frac{20}{15} + \frac{24}{15}$ $-20/15+24/15$

= $\frac{4}{15}$ $4/15$

ANSWER: $\frac{4}{15}$ $4/15$

How do you find h(−1)h(-1) given h(n)=43n+85h(n)=4/3n+8/5?