Question

How do you find `h(-1)` given `h(x)=-x^2-3`?

Answer 1

See a solution process below:

Explanation:

To fing `h(-1)` substitute `color(red)(-1)` for each occurrence of `color(red)(-1)` and the calculate the result:

`h(color(red)(x)) = -color(red)(x)^2 - 3` becomes:

`h(color(red)(-1)) = -color(red)((-1))^2 - 3`

`h(color(red)(-1)) = -1 - 3`

`h(color(red)(-1)) = -4`