How do you find $h (10)$ $h(10)$ given $h (x) = - x^{2} - x$ $h(x)=-x^2-x$ ?

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Answer 1 · 2016-08-18T23:51:32

$h (10) = 110$ $h(10) = 110$

$h (x) = - x^{2} - x$ $h(color(red)(x))=-color(red)(x)^2-color(red)(x)$

$h (10)$ $h(10)$ means that x = 10. So each x is replaced by 10

$h (10) = - 10^{2} - 10$ $h(color(red)(10))=-color(red)(10)^2-color(red)(10)$

$h (10) = - 100 - 10 = - 110$ $h(color(red)(10)) = -100 -10 = -110$

Remember that $y = f (x)$ $y = f(x)$

$y = h (x)$ $y = h(x)$

$y = h (10) = - 110$ $y = h(10) = -110$

means that for this function, when

$x = 10, y = - 110$ $x = 10, y= -110$

How do you find h(10)h(10)h(10) given h(x)=-x^2-xh(x)=−x2−xh(x)=-x^2-x?