How do you find $h (- 2)$ $h(-2)$ given $h (t) = - 2 \cdot 5^{- t - 1}$ $h(t)=-2*5^(-t-1)$ ?

Question

How do you find $h (- 2)$ $h(-2)$ given $h (t) = - 2 \cdot 5^{- t - 1}$ $h(t)=-2*5^(-t-1)$ ?

1 Answer

Impact of this question

8514 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-03T17:48:03

$= - 10$ $=-10$

Explanation:

$h (t) = - 2 (5^{- t - 1})$ $h(t)=-2(5^(-t-1))$
or
$h (- 2) = - 2 (5^{- (- 2) - 1})$ $h(-2)=-2(5^(-(-2)-1))$
$= - 2 (5^{2 - 1})$ $=-2(5^(2-1))$
$= - 2 (5^{1})$ $=-2(5^1)$
$= - 2 (5)$ $=-2(5)$
$= - 10$ $=-10$

Science

Math

Humanities

... and beyond

How do you find $h (- 2)$ $h(-2)$ given $h (t) = - 2 \cdot 5^{- t - 1}$ $h(t)=-2*5^(-t-1)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find h(−2)h(-2) given h(t)=−2⋅5−t−1h(t)=-2*5^(-t-1)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find $h (- 2)$ $h(-2)$ given $h (t) = - 2 \cdot 5^{- t - 1}$ $h(t)=-2*5^(-t-1)$ ?