How do you find $h (- 2 a)$ $h(-2a)$ given $h (a) = a^{2} + 4$ $h(a)=a^2+4$ ?

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Answer 1 · 2018-04-13T13:36:43

$4 a^{2} + 4$ $4a^2+4$

Since $h (a) = a^{2} + 4$ $h(a) = a^2+4$

Then $h (- 2 a) = {(- 2 a)}^{2} + 4$ $h(-2a) = (-2a)^2+4$ = $4 a^{2} + 4$ $4a^2+4$

How do you find h(−2a)h(-2a) given h(a)=a2+4h(a)=a^2+4?